11x^2+4x-12=0

Solution for 11x^2+4x-12=0 equation:

11x^2+4x-12=0

a = 11; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·11·(-12)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{34}}{2*11}=\frac{-4-4\sqrt{34}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{34}}{2*11}=\frac{-4+4\sqrt{34}}{22}
$